Section 4.1: Introduction to Angles
Learning Objectives
In this section you will:
- Draw angles in standard position.
- Convert between degrees and radians.
- Find coterminal angles.
- Find the length of a circular arc.
- Use linear and angular speed to describe motion on a circular path.
A golfer swings to hit a ball over a sand trap and onto the green. An airline pilot maneuvers a plane toward a narrow runway. A dress designer creates the latest fashion. What do they all have in common? They all work with angles, and so do all of us at one time or another. Sometimes we need to measure angles exactly with instruments. Other times we estimate them or judge them by eye. Either way, the proper angle can make the difference between success and failure in many undertakings. In this section, we will examine properties of angles.
Drawing Angles in Standard Position
Properly defining an angle first requires that we define a ray. A ray is a directed line segment. It consists of one point on a line and all points extending in one direction from that point. The first point is called the endpoint of the ray. We can refer to a specific ray by stating its endpoint and any other point on it. The ray pictured below can be named as ray EF, or in symbol form $\overrightarrow{EF}$.
Angle
An angle is the union of two rays having a common endpoint. The endpoint is called the vertex of the angle, and the two rays are the sides of the angle.
The angle shown below is formed from $\overrightarrow{ED}$ and $\overrightarrow{EF}$. Angles can be named using a point on each ray and the vertex, such as angle DEF, or in symbol form $\angle DEF$.
Greek letters are often used as variables for the measure of an angle. The table below has a list of Greek letters commonly used to represent angles, and a sample angle is shown below.
Angle creation is a dynamic process. We start with two rays lying on top of one another. We leave one fixed in place, and rotate the other. The fixed ray is the initial side, and the rotated ray is the terminal side. In order to identify the different sides, we indicate the rotation with a small arrow close to the vertex as shown below.
Angle creation
Imagine two rays starting at the same place. Leave one in place (this is the initial side) and sweep the other ray around (this is the terminal side). This creates an angle, as pictured below.
You can play around with dynamically creating an angle by following this geogebra link.
As we discussed at the beginning of the section, there are many applications for angles, but in order to use them correctly, we must be able to measure them.
Measuring Angles
The measure of an angle is the amount of rotation from the initial side to the terminal side.
Probably the most familiar unit of angle measurement is the degree.
Degree
One degree is $\frac{1}{360}$ of a circular rotation, so a complete circular rotation contains 360 degrees.
An angle measured in degrees should always include the unit “degrees” after the number, or include the degree symbol °. For example, 90 degrees = 90°.
To formalize our work, we will begin by drawing angles on an x-y coordinate plane. Angles can occur in any position on the coordinate plane, but for the purpose of comparison, the convention is to illustrate them in the same position whenever possible.
An angle in standard position
An angle is in standard position if its vertex is located at the origin, and its initial side extends along the positive x-axis. See the image below.
Positive and Negative Angles
If the angle is measured in a counterclockwise direction from the initial side to the terminal side, the angle is said to be a positive angle. If the angle is measured in a clockwise direction, the angle is said to be a negative angle.
Drawing an angle in standard position always starts the same way—draw the initial side along the positive x-axis. To place the terminal side of the angle, we must calculate the fraction of a full rotation the angle represents. We do that by dividing the angle measure in degrees by 360°. For example, to draw a 90° angle, we calculate that $\frac{90°}{360°}=\frac{1}{4}$. So, the terminal side will be one-fourth of the way around the circle, moving counterclockwise from the positive x-axis. To draw a 360° angle, we calculate that $\frac{360^\circ}{360^\circ} = 1$. So the terminal side will be 1 complete rotation around the circle, moving counterclockwise from the positive x-axis. In this case, the initial side and the terminal side overlap. See below.
Since we define an angle in standard position by its terminal side, we have a special type of angle whose terminal side lies on an axis, a quadrantal angle. This type of angle can have a measure of 0°, 90°, 180°, 270°, or 360°. See below.
Quadrantal Angles
An angle is a quadrantal angle if its terminal side lies on an axis, including 0°, 90°, 180°, 270°, or 360°.
Given an angle measured in degrees, draw the angle in standard position.
- Express the angle measure as a fraction of 360°.
- Reduce the fraction to simplest form.
- Draw an angle that contains that same fraction of the circle, beginning on the positive x-axis and moving counterclockwise for positive angles and clockwise for negative angles.
A. Sketch an angle of $30^\circ$ in standard position
Divide the angle measure by $360^\circ$: $$\frac{30^\circ}{360^\circ} = \frac{1}{12}$$ To rewrite the fraction in a more familiar fraction, we can recognize that $$\frac{1}{12} = \frac{1}{3}\left(\frac{1}{4}\right)$$ One-twelfth equals one-third of a quarter, so by dividing a quarter rotation into thirds, we can sketch a line at 30°, as in the picture below:
B. Sketch an angle of −135° in standard position.
Divide the angle measure by $360^\circ$: $$\frac{-135^\circ}{360^\circ} = -\frac{3}{8}$$ In this case, we can recognize that $$-\frac{3}{8} = -\frac{3}{2}\left(\frac{1}{4}\right)$$ Three-eighths is one and one-half times a quarter, so we place a line by moving clockwise one full quarter and one-half of another quarter, as shown below:
Converting Between Degrees and Radians
Dividing a circle into 360 parts is an arbitrary choice, although it creates the familiar degree measurement. We may choose other ways to divide a circle. To find another unit, think of the process of drawing a circle. Imagine that you stop before the circle is completed. The portion that you drew is referred to as an arc. An arc may be a portion of a full circle, a full circle, or more than a full circle, represented by more than one full rotation. The length of the arc around an entire circle is called the circumference of that circle.
Arc
A portion of a full circle.
An arc may be a portion of a full circle, a full circle, or more than a full circle, represented by more than one full rotation. The length of the arc around an entire circle is called the circumference of that circle.
Circumference
The full distance around a circle.
The formula for the circumference of a circle is $C=2\pi r$.
If we divide both sides of this circumference equation by $r$, we create the ratio of the circumference, which is always $2\pi$, to the radius, regardless of the length of the radius. So the circumference of any circle is $2\pi\approx 6.28$ times the length of the radius. That means that if we took a string as long as the radius and used it to measure consecutive lengths around the circumference, there would be room for six full string-lengths and a little more than a quarter of a seventh, as shown below
This brings us to our new angle measure. One radian is the measure of a central angle of a circle that intercepts an arc equal in length to the radius of that circle. A central angle is an angle formed at the center of a circle by two radii. Check out the animation below to see how a radian is formed:
(GIF attribution: By Lucas Vieira - Own work, Public Domain, https://commons.wikimedia.org/w/index.php?curid=25112326))
So this is how we form a radian: take the radius of the circle, lay it along the circumference. Connect the endpoints of that radius-length curve to the center of the circle. The angle formed is one radian.
Radian
A radian is the measure of a central angle of a circle that intercepts an arc equal in length to the radius of that circle.Note that when an angle is described without a specific unit, it refers to radian measure. For example, an angle measure of 3 indicates 3 radians. In fact, radian measure is dimensionless, since it is the quotient of a length (circumference) divided by a length (radius) and the length units cancel.
Because degrees and radians both measure angles, we need to be able to convert between them. We can easily do so using a proportion where $\theta$ is the measure of the angle in degrees and $\theta_R$ is the measure of the angle in radians. Since we know that a whole rotation of a circle is $2 \pi$ radians, it follows that half a circle is $\pi$ radians. In degrees, half a circle is $180^\circ$. So we create a proportion where we compare radians to degrees: $$\frac{\theta ^\circ}{180^\circ} = \frac{\theta_R}{\pi}$$ We can solve this proportion for either $\theta^\circ$ or $\theta_R$ to see how to convert between degrees and radians:
Converting Between Degrees and Radians
To change degrees into radians, use the formula: $\theta^\circ \cdot \frac{\pi}{180^\circ}=\theta_R $
To change radians into degrees, use the formula: $ \theta_R \cdot \frac{180^\circ}{\pi}=\theta^\circ $
A. $\frac{\pi}{6}$
To change radians into degrees, multiply by $\frac{180}{\pi}$:
$$\frac{\pi}{6}\cdot\frac{180}{\pi}$$Now, typically we want to cancel and simplify as much as possible:
$$=\frac{\cancel{\pi}}{_1 \cancel{6}}\frac{\cancel{180}^{30}}{\cancel{\pi}}$$ $$=30^\circ$$B. $3$
$15^\circ$
To convert degrees to radians, multiply by $\frac{\pi}{180^\circ}$ (so the "degrees" label cancels, like in dimensional analysis!)
$$15^\circ \cdot \frac{\pi}{180^\circ}$$Now, we usually will write our answer in terms of $\pi$, and simplify the numerical part of the fraction as much as we can:
$$=15^\cancel{\circ} \cdot \frac{\pi}{180^\cancel{\circ}}$$ $$=\frac{^1 \cancel{15}\pi}{\cancel{180}_{12}}$$ $$=\frac{\pi}{12}$$Finding Coterminal Angles
Converting between degrees and radians can make working with angles easier in some applications. For other applications, we may need another type of conversion. Negative angles and angles greater than a full revolution are more awkward to work with than those in the range of 0° to 360°, or 0 to $2\pi$. It would be convenient to replace those out-of-range angles with a corresponding angle within the range of a single revolution.
It is possible for more than one angle to have the same terminal side. Look at the figure below. The angle of 140° is a positive angle, measured counterclockwise. The angle of –220° is a negative angle, measured clockwise. But both angles have the same terminal side. If two angles in standard position have the same terminal side, they are coterminal angles. Every angle greater than 360° or less than 0° is coterminal with an angle between 0° and 360°, and it is often more convenient to find the coterminal angle within the range of 0° to 360° than to work with an angle that is outside that range.
Any angle has infinitely many coterminal angles because each time we add 360° to that angle—or subtract 360° from it—the resulting value has a terminal side in the same location. For example, 100° and 460° are coterminal for this reason, as is −260°. You can experiment with coterminal angles using the interactive applet found through this link by Math Open Reference.
Coterminal Angles
Coterminal angles are two angles in standard position that have the same terminal side.
If an angle is larger than $360^\circ$ or $2\pi$ radians, you can find a smaller coterminal angle by subtracting a full revolution of a circle; that is, subtract $360^\circ$ or $2\pi$ radians.
If an angle is negative, you can find a positive coterminal angle by adding a full revolution of a circle; that is, add $360^\circ$ or $2\pi$ radians.
Find the smallest positive angle that is coterminal with each of the following:
A. $1529^\circ$
Since this angle is larger than $360^\circ$, we subtract a full revolution of a circle:
$$1529^\circ - 360^\circ = 1169^\circ$$That's still bigger than $360^\circ$, so we subtract another revolution:
$$1169^\circ - 360^\circ = 809^\circ$$and another
$$809^\circ - 360^\circ = 449^\circ$$and one more revolution should get us there...
$$449^\circ - 360^\circ = 89^\circ$$Now our angle is less than $360^\circ$, so we know we have the smallest possible positive coterminal angle
B. $-\frac{41\pi}{18}$
This angle is negative, and in radians, so we'll want to add a full revolution in radians: $2\pi$
$$-\frac{41\pi}{18}+2\pi$$ Now, to add, we want a common denominator. So, we can rewrite $2\pi$ as $2\pi\cdot\frac{18}{18} = \frac{36\pi}{18}$: $$-\frac{41\pi}{18}+2\pi$$ $$=-\frac{41\pi}{18}+\frac{36\pi}{18}$$ $$=-\frac{5\pi}{18}$$This is still a negative coterminal angle, so we need to add another revolution, $\frac{36\pi}{18}$: $$-\frac{5\pi}{18}+\frac{36\pi}{18}$$ $$=\frac{31 \pi}{18}$$
That's our smallest positive coterminal angle.
Determining the Length of an Arc
An arc of a circle is a small chunk of its circumference, as pictured below:
In this figure, we have an arc of length $s$ subtended by an angle measure of $\theta$ in a circle of radius $r$. We can compare this small portion of the circle to the whole circle by setting up a proportion. That proportion will look slightly different depending on whether we have the central angle, $\theta$, given in degrees or in radians. In general, though, we want to compare the part of the circle to the whole. In the following proportion, we put the partial arc information on the left side of the proportion, and the whole circle information on the right: $$\frac{\text{arc length}}{\text{central angle subtending the arc}} = \frac{\text{circumference}}{\text{total angle measure of circle}}$$ Symbolically, that is... $$\frac{s}{\theta} = \frac{2\pi r}{\text{total angle measure of circle}}$$ What we use for that total angle measure will depend on whether we are given $\theta$ in degrees or radians.
Calculating length of an arc:
Degrees:To find the length of arc $s$ subtended by angle $\theta^\circ$ in a circle of radius $r$, use the proportion $$\frac{s}{\theta} = \frac{2\pi r}{360^\circ}$$.
Radians: To find the length of arc $s$ subtended by angle $\theta_R$ in a circle of radius $r$, use the proportion $$\frac{s}{\theta_R} = \frac{2\pi r}{2\pi}$$ that is, $$\frac{s}{\theta_R} = r$$ or even more simply... $$s = r\cdot \theta_R$$
A. Find the arc length along a circle of radius 10 units subtended by an angle of $215^\circ$.
Let's gather up our variables: $r = 10$, $\theta^\circ = 215^\circ$, $s = $unknown. Since the angle is given in degrees, we'll use the degrees version of our proportions: $$\frac{s}{\theta} = \frac{2\pi r}{360^\circ}$$ $$\frac{s}{215} = \frac{2\pi(10)}{360^\circ}$$ To solve for $s$, we multiply both sides of the equation by $215$ and evaluate from there. $$s = 215\cdot \frac{20\pi}{360} \approx 37.52$$
B. Find the arc length along a circle of radius 3 units subtended by an angle of $\frac{3\pi}{4}$.
Here we have $r = 3$, $\theta = \frac{3\pi}{4}$. Since our angle is given in radians, we can use the simpler formula $s = r\theta_R$: $$s = 3\cdot \frac{3\pi}{4} = \frac{9\pi}{4}$$
Assume the orbit of Mercury around the sun is a perfect circle. Mercury is approximately 36 million miles from the sun.
In one Earth day, Mercury completes 0.0114 of its total revolution. How many miles does it travel in one day?
Figuring out our initial variables is a little trickier here. We know $r = 36$ (thinking of the sun as the center of our big circle for simplicity's sake). We also know Mercury will complete 0.0114 of its revolution. So, in terms of angles, that's $0.0114\cdot 360^\circ = 4.104^\circ$. So $\theta = 4.104^\circ$. Now we create our degrees proportion: $$\frac{s}{4.104}=\frac{2\pi(36)}{360}$$ $$s = 4.104\cdot \frac{72\pi}{360} \approx 2.58$$ So Mercury has travelled approximately 2.58 million miles.
The length of an arc is $3\pi$ centimeters on a circle of radius 10 cm. What is the measure (in degrees) of the central angle that subtends this arc?
Here, we are given a slightly different set of information. We know $r = 10$ and $s = 3\pi$ and we want to solve for $\theta$ in degrees. We can still use our degrees proportion: $$\frac{s}{\theta} = \frac{2\pi r}{360^\circ}$$ $$\frac{3\pi}{\theta} = \frac{2\pi(10}{360}$$ So, to solve for $\theta$, we can first cross multiply to get: $$3\pi\cdot 360 = 20\pi\cdot \theta$$ then divide by $20\pi$ to isolate $\theta$: $$\frac{3\pi\cdot 360}{20\pi} = \theta$$ $$\theta = 54^\circ$$
Finding the area of a sector
A sector is a chunk of a circle, like a pizza slice. In the image below, a sector subtended by an angle of measure $\theta$ is shaded in yellow:
The good news here is that finding the area of that pizza slice is basically the same process as finding an arc length, but now we'll use the area formula in our proportion instead of the circumference. $$\frac{\text{sector area}}{\text{central angle subtending the sector}} = \frac{\text{circle area}}{\text{total angle measure of circle}}$$ Symbolically, that is... $$\frac{a}{\theta} = \frac{\pi r^2}{\text{total angle measure of circle}}$$ What we use for that total angle measure will depend on whether we are given $\theta$ in degrees or radians.
Calculating area of an sector:
Degrees: To find the area of a sector $a$ subtended by angle $\theta^\circ$ in a circle of radius $r$, use the proportion $$\frac{a}{\theta} = \frac{\pi r^2}{360^\circ}$$.
Radians: To find the area of a sector $a$ subtended by angle $\theta_R$ in a circle of radius $r$, use the proportion $$\frac{a}{\theta_R} = \frac{\pi r^2}{2\pi}$$ that is, $$\frac{a}{\theta_R} = \frac{r^2}{2}$$ or even more simply... $$a = \frac{r^2}{2}\cdot \theta_R$$
An automatic lawn sprinkler sprays a distance of 20 feet while rotating 30 degrees, as shown below. What is the area of the sector of grass the sprinkler waters?
The angle is given in degrees, and we want to find a sector area, so we use the proportion $$\frac{a}{\theta} = \frac{\pi r^2}{360^\circ}$$ Here, $\theta = 30^\circ$, $r = 20$ and $a$ is unknown. $$\frac{a}{30} = \frac{\pi(20^2)}{360}$$ Multiply both sides by 30 to isolate $a$ and evaluate. $$a = \frac{400\pi}{360}\cdot 30 \approx 104.72$$ The area is about 104.72 $ft^2$.
In central pivot irrigation, a large irrigation pipe on wheels rotates around a center point. A farmer has a central pivot system with a radius of 400 meters. If water restrictions only allow her to water 150 thousand square meters a day, what angle should she set the system to cover? Write the answer in radian measure to two decimal places.
Here, we already know the sector area, and we're looking for an angle in radians, so we can use the proportion: $$\frac{a}{\theta_R} = \frac{r^2}{2}$$ where $a = 150000$, $r = 400$ and $\theta_R$ is unknown. $$\frac{150000}{\theta_R} = \frac{400^2}{2}$$ Multiply by $\theta_R$: $$150000 = 80000\cdot \theta_R$$ Then isolate $\theta_R$: $$\frac{150000}{80000} = \theta_R$$ So the angle is approximately 1.875 radians.
Use Linear and Angular Speed to Describe Motion on a Circular Path
In addition to finding the area of a sector, we can use angles to describe the speed of a moving object. An object traveling in a circular path has two types of speed. Linear speed is speed along a straight path and can be determined by the distance it moves along (its displacement) in a given time interval. For instance, if a wheel with radius 5 inches rotates once a second, a point on the edge of the wheel moves a distance equal to the circumference, or 10π inches, every second. So the linear speed of the point is 10π in./s. Really here, we're talking about the relationship between distance, rate, and time, which you may recognize as the equation $$d = rt$$ We want to reframe this a bit, so we'll think of the rate as $v$ and the distance as $s$ (like arc length): $$s = vt$$ If we solve for the speed, $v$, we have $$v = \frac{s}{t}$$
Angular speed results from circular motion and can be determined by the angle through which a point rotates in a given time interval. In other words, angular speed is angular rotation per unit time. So, for instance, if a gear makes a full rotation every 4 seconds, we can calculate its angular speed as $\frac{360\text{degrees}}{4\text{ seconds}} = 90$ degrees per second. Angular speed can be given in radians per second, rotations per minute, or degrees per hour, for example. The equation for angular speed is as follows, where $\omega$ (read as omega) is angular speed, θ is the angle traversed, and t is time: $$\omega = \frac{\theta}{t}$$
Combining the definition of angular speed with the arc length equation, s=rθ, we can find a relationship between angular and linear speeds. The angular speed equation can be solved for θ, giving θ=ωt. Substituting this into the arc length equation gives: $$s = r\theta$$ $$s = r\omega t$$ Substituting this into the linear speed equation gives: $$v = \frac{s}{t}$$ $$v = \frac{r\omega t}{t}$$ $$v = r\omega$$.
Angular and Linear Speed
As a point moves along a circle of radius $r$, its angular speed, $\omega$, is the angular rotation $\theta$ per unit time, $t$: $$\omega = \frac{\theta}{t}$$ The linear speed, $v$, of the point can be found as the distance traveled, arc length $s$, per unit time, $t$: $$v = \frac{s}{t}$$ When the angular speed is measured in radians per unit time, linear speed and angular speed are related by the equation $$v = r\omega$$ This equation states that the angular speed in radians, ω, representing the amount of rotation occurring in a unit of time, can be multiplied by the radius r to calculate the total arc length traveled in a unit of time, which is the definition of linear speed.
A water wheel, shown below, completes 1 rotation every 5 seconds. Find the angular speed in radians per second.
The wheel completes 1 rotation, or passes through an angle of 2π radians in 5 seconds, so the angular speed would be $$\omega = \frac{2\pi}{5} \approx 1.257$$ That's about 1.257 radians per second.
A bicycle has wheels 28 inches in diameter. A tachometer determines the wheels are rotating at 180 RPM (revolutions per minute). Find the speed the bicycle is traveling down the road.
Here, we have an angular speed and need to find the corresponding linear speed, since the linear speed of the outside of the tires is the speed at which the bicycle travels down the road.
We begin by converting from rotations per minute to radians per minute. It can be helpful to utilize the units to make this conversion: $$180\frac{\cancel{\text{rotations}}}{\text{minute}}\cdot\frac{2\pi \text{ radians}}{\cancel{\text{ rotation}}} = 360\pi \frac{\text{radians}}{\text{minute}}$$ Using the formula from above along with the radius of the wheels, we can find the linear speed: $$v = (14 \text{ inches})(360\pi \frac{\text{radians}}{\text{minute}})$$ $$=5040\pi \frac{\text{inches}}{\text{minute}}$$
Remember that radians are a unitless measure, so it is not necessary to include them.
Finally, we may wish to convert this linear speed into a more familiar measurement, like miles per hour. $$5040\pi \frac{\text{inches}}{\text{minute}}\cdot \frac{1\text{feet}}{12\text{inches}}\cdot \frac{1\text{mile}}{5280\text{feet}}\cdot \frac{60\text{minutes}}{1\text{hour}}$$ $$\approx 14.99 \text{ miles per hour}$$
A bicycle has wheels 3/4 feet in radius. If the bicycle is traveling at 20 ft/sec, what is the angular speed of the wheel in rpms (rotations per minute)?
Let's first focus on matching our units. The bike's speed is measured in feet per second, and we want our final speed in rotations per minute, so let's convert the bike's speed into feet per minute: $$20\frac{\text{feet}}{\text{second}} \cdot \frac{60 \text{ seconds}}{1\text{ minute}} = 1200 \text{ ft/min}$$
Now, we know our linear speed is $v = 1200 \text{ ft/min}$ and the radius is $r = 3/4\text{ ft}$, so we apply these values in our $v = \omega r$ formula: $$1200 \frac{\text{ft}}{\text{min}} = \omega \cdot \frac34 \text{ft}$$ $$1200\cdot \frac43 \frac{\text{ ?}}{\text{min}} = \omega$$ $$\omega = 1600 \frac{\text{ ?}}{\text{min}}$$
Now, what should that unit in the numerator be? Remember, in our equation by default, the angular speed is measured in radians per unit time; technically radians are unit-less, so when we're solving for an angular speed, it looks like one of the labels is dropping out entirely. We can think of that label in the numerator as being radians!
We have our angular speed, but our final answer is supposed to be in rpms, so we need to do another conversion. There are $2\pi$ radians in a revolution of a circle, so $$1600 \frac{\text{radians}}{\text{minute}} \cdot \frac{1\text{ revolution}}{2\pi \text{ radians}} = \frac{800}{\pi} \text{ rpms}$$.
Exercises
In the following exercises, convert the angle from degree measure into radian measure, giving the exact value in terms of $\pi$.
1. $0^{\circ}$
2. $240^{\circ}$
3. $135^{\circ}$
4. $-270^{\circ}$
5. $-315^{\circ}$
6. $150^{\circ}$
7. $45^{\circ}$
8. $-225^{\circ}$
1. 0
2. $\frac{4\pi}{3}$
3. $\frac{3\pi}{4}$
4. $-\frac{3\pi}{2}$
5. $-\frac{7\pi}{4}$
6. $\frac{5\pi}{6}$
7. $\frac{\pi}{4}$
8. $-\frac{5\pi}{4}$
In the following exercises, convert the angle from radian measure into degree measure.
9. $\pi$
10. $-\frac{2\pi}{3}$
11. $\frac{7\pi}{6}$
12. $\frac{11\pi}{6}$
13. $\frac{\pi}{3}$
14. $\frac{5\pi}{3}$
15. $-\frac{\pi}{6}$
16. $\frac{\pi}{2}$
9. $180^{\circ}$
10. $-120^{\circ}$
11. $210^{\circ}$
12. $330^{\circ}$
13. $60^{\circ}$
14. $300^{\circ}$
15. $-30^{\circ}$
16. $90^{\circ}$
For the following exercises, find the angle between $0^\circ$ and $360^\circ$ that is coterminal to the given angle.
17. $-40^\circ$
18. $-110^\circ$
19. $700^\circ$
20. $1400^\circ$
17. $320^\circ$
18. $250^\circ$
19. $340^\circ$
20. $320^\circ$
For the following exercises, find the angle between 0 and 2π in radians that is coterminal to the given angle.
21. $-\frac{\pi}{9}$
22. $\frac{10\pi}{3}$
23. $\frac{13\pi}{6}$
24. $\frac{44\pi}{9}$
21. $\frac{17\pi}{9}$
22. $\frac{4\pi}{3}$
23. $\frac{\pi}{6}$
24. $\frac{8\pi}{9}$
25. A yo-yo which is 2.25 inches in diameter spins at a rate of 4500 revolutions per minute. How fast is the edge of the yo-yo spinning in miles per hour? Round your answer to two decimal places.
26. How many revolutions per minute would the yo-yo in the previous exercise have to complete if the edge of the yo-yo is to be spinning at a rate of 42 miles per hour? Round your answer to two decimal places.
27. In the yo-yo trick `Around the World,' the performer throws the yo-yo so it sweeps out a vertical circle whose radius is the yo-yo string. If the yo-yo string is 28 inches long and the yo-yo takes 3 seconds to complete one revolution of the circle, compute the speed of the yo-yo in miles per hour. Round your answer to two decimal places.
28. A computer hard drive contains a circular disk with diameter 2.5 inches and spins at a rate of 7200 revolutions per minute. Find the linear speed of a point on the edge of the disk in miles per hour.
29. A rock got stuck in the tread of my tire and when I was driving 70 miles per hour, the rock came loose and hit the inside of the wheel well of the car. How fast, in miles per hour, was the rock traveling when it came out of the tread? (The tire has a diameter of 23 inches.)
30. The Giant Wheel at Cedar Point is a circle with diameter 128 feet which sits on an 8 foot tall platform making its overall height is 136 feet. It completes two revolutions in 2 minutes and 7 seconds. Assuming the riders are at the edge of the circle, how fast are they traveling in miles per hour?
25. About 30.12 miles per hour
26. About 6274.52 revolutions per minute
27. About 3.33 miles per hour
28. About 53.55 miles per hour
29. 70 miles per hour
30. About 4.32 miles per hour
In the following exercises, compute the areas of the circular sectors with the given central angles and radii.
31. $\theta = \dfrac{\pi}{6}, \; r = 12$
32. $\theta = \dfrac{5\pi}{4}, \; r = 100$
33. $\theta = 330^{\circ}, \; r = 9.3$
34. $\theta =\pi, \; r = 1$
35. $\theta = 240^{\circ}, \; r = 5$
36. $\theta = 1^{\circ}, \; r = 117$
31. $12\pi$ square units
32. $6250\pi$ square units
33. $79.2825\pi \approx 249.07$ square units
34. $\dfrac{\pi}{2}$ square units
35. $\dfrac{50\pi}{3}$ square units
36. $38.025 \pi \approx 119.46$ square units
37. Imagine a rope tied around the Earth at the equator. Show that you need to add only $2\pi$ feet of length to the rope in order to lift it one foot above the ground around the entire equator. (You do NOT need to know the radius of the Earth to show this.)
For additional exercises, check out the bottom of the Section 7.1 at OpenStax by following this link.
Homework Set
- Convert $80^\circ$ to radians.
- What is the exact radian measure of a $-182^\circ$ angle?
- Convert $\frac{3\pi}{7}$ to degrees.
- Convert $\frac{11\pi}{18}$ to degrees.
- Find an angle between $0^\circ$ and $360^\circ$ that is coterminal with each of the following angles.
- $491^\circ$
- $-29^\circ$
- $-1715^\circ$
- $4572^\circ$
- Find an angle between $0$ and $2\pi$ that is coterminal with each of the following angles.
- $-\frac{104\pi}{11}$
- $-\frac{33\pi}{10}$
- $\frac{17\pi}{6}$
- $\frac{11\pi}{10}$
- Find the length of an arc if the radius of the arc is 6 inches and the measure of the central angle is $\frac{9\pi}{8}$.
- A Ferris wheel has a diameter of 50 feet. How far has a person on the Ferris wheel traveled when they have moved $270^\circ$?
- Find the area of the sector of a circle with radius 6 km formed by a central angle of $\frac{\pi}{6}$.
- A hamster runs at a speed of 7 cm/sec in a wheel with radius 10 cm.
- What is the angular velocity of the wheel in radians/sec?
- How fast will the wheel spin in revolutions per minute?
- A toy car has wheels with 10 cm radius. The wheels are spinning at a rate of one revolution in 6 seconds.
- What is the angular velocity of the wheel in radians/sec?
- At what linear velocity is the hamster running?
- A truck with 36 inch diameter wheels is traveling 45 mph.
- Find the angular speed of the wheels in rad/min.
- How many revolutions per minute do the wheels make?
- A central angle has a measure of 162 degrees and the intercepted arc's sector has an area measure of 84 $cm^2$. What is the radius of the circle? Round answers to three decimal places when necessary.